20p^2+44p-15=0

Solution for 20p^2+44p-15=0 equation:

20p^2+44p-15=0

a = 20; b = 44; c = -15;
Δ = b2-4ac
Δ = 442-4·20·(-15)
Δ = 3136
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3136}=56$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(44)-56}{2*20}=\frac{-100}{40}
=-2+1/2
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(44)+56}{2*20}=\frac{12}{40}
=3/10
$